Unitary Method, Ratio and Proportion - Complete Guide for Class 6 CBSE Maths
Introduction to Unitary Method, Ratio and Proportion
Understanding the unitary method, ratios, and proportions forms the foundation of quantitative reasoning in mathematics. These concepts help students solve real-world problems involving comparisons, scaling, and proportional relationships. This comprehensive guide covers all aspects of these topics as per the CBSE Class 6 syllabus, with detailed explanations, solved examples, and practice exercises.
What is the Unitary Method?
Definition
The unitary method is a technique where we first find the value of a single unit from a given quantity, and then calculate the value of the required number of units. This method is particularly useful for solving problems involving direct and inverse proportions.
Key Principles
- To get more, we multiply - When finding the value of multiple units from one unit
- To get less, we divide - When finding the value of one unit from multiple units
Real-World Applications
- Shopping calculations (price per item)
- Speed and distance problems
- Work and time calculations
- Currency conversion
- Recipe scaling
Examples of Unitary Method Problems with Step-by-Step Solutions
Example 1: Direct Proportion Problem
Problem: If 15 tins contain 234 kg of oil, how much oil will be in 10 such tins?
Solution:
- Step 1: Find oil in 1 tin
- 15 tins contain = 234 kg
- 1 tin contains = 234 ÷ 15 kg = 15.6 kg
- Step 2: Find oil in 10 tins
- 10 tins contain = 15.6 × 10 = 156 kg
Answer: 10 tins contain 156 kg of oil.
Example 2: Cost Calculation
Problem: If 5 bars of soap cost ₹31, find the cost of 2 dozen such bars.
Solution:
- Step 1: Find cost of 1 bar
- 5 bars cost = ₹31
- 1 bar costs = 31 ÷ 5 = ₹6.20
- Step 2: Find cost of 24 bars (2 dozen)
- 24 bars cost = 6.20 × 24 = ₹148.80
Answer: 2 dozen bars cost ₹148.80.
Example 3: Distance and Fuel Consumption
Problem: If 12 litres of petrol covers 222 km, how many kilometres can be covered with 22 litres?
Solution:
- Step 1: Find distance per litre
- 12 litres cover = 222 km
- 1 litre covers = 222 ÷ 12 = 18.5 km
- Step 2: Find distance with 22 litres
- 22 litres cover = 18.5 × 22 = 407 km
Answer: The car will travel 407 km with 22 litres of petrol.
How to Solve Inverse Proportion Using Unitary Method
Understanding Inverse Proportion
In inverse proportion, when one quantity increases, the other decreases proportionally. The product of the two quantities remains constant.
Method for Solving Inverse Proportion
Formula: If a₁ × b₁ = a₂ × b₂, then the quantities are in inverse proportion.
Example Problem
Problem: 6 workers can complete a task in 15 days. How many days will 10 workers take to complete the same task?
Solution:
- Step 1: Find work in "worker-days"
- Total work = 6 workers × 15 days = 90 worker-days
- Step 2: Calculate days for 10 workers
- 10 workers will take = 90 ÷ 10 = 9 days
Answer: 10 workers will complete the task in 9 days.
Key Insight
As the number of workers increases, the number of days decreases - this is inverse proportion.
Understanding Ratios
Definition
A ratio is a comparison between two quantities of the same kind and in the same unit. It shows how many times one quantity is contained in another.
Notation
The ratio of 'a' to 'b' is written as:
- a : b
- a/b (as a fraction)
Important Points About Ratios
- Same Units Required: Both quantities must be in the same unit
- Order Matters: The ratio 3:4 is different from 4:3
- No Units in Ratio: Ratios are pure numbers without units
- Terms: In a:b, 'a' is the antecedent and 'b' is the consequent
Examples with Unit Conversion
Example 1: Time Ratio
Find the ratio of 225 ml to 3 litres
Solution:
- Convert to same unit: 3 litres = 3000 ml
- Ratio = 225 : 3000
- Simplify: 225 : 3000 = 9 : 120 = 3 : 40
Answer: 3:40
Example 2: Money Ratio
Find the ratio of 65 paise to ₹5
Solution:
- Convert to same unit: ₹5 = 500 paise
- Ratio = 65 : 500
- Simplify: 65 : 500 = 13 : 100
Answer: 13:100
Equivalent Ratios
Definition
Ratios obtained by multiplying or dividing both terms by the same non-zero number are called equivalent ratios.
Properties
- a : b = ac : bc (multiplying both terms by c)
- a : b = (a÷c) : (b÷c) (dividing both terms by c)
Examples
- 6 : 10 = 3 : 5 (dividing by 2)
- 6 : 10 = 12 : 20 (multiplying by 2)
- All these ratios are equivalent
Simplest Form of Ratios
Definition
A ratio is in its simplest form or lowest terms when the antecedent and consequent have no common factor except 1.
Method to Simplify
- Find the HCF of both terms
- Divide both terms by their HCF
Example
Simplify the ratio 42:63
Solution:
- HCF(42, 63) = 21
- 42 ÷ 21 = 2
- 63 ÷ 21 = 3
- Simplest form = 2:3
Comparing Ratios
Method
To compare two ratios, make their denominators equal (find LCM), then compare numerators.
Example
Which is greater: 2:3 or 3:4?
Solution:
- LCM of 3 and 4 = 12
- 2/3 = (2×4)/(3×4) = 8/12
- 3/4 = (3×3)/(4×3) = 9/12
- Since 9 > 8, therefore 3/4 > 2/3
Answer: 3:4 is greater than 2:3
Understanding Proportion
Definition
The equality of two ratios is called proportion. If a:b = c:d, we say that a, b, c, d are in proportion, written as a:b::c:d.
Terms in Proportion
- Extremes: First and fourth terms (a and d)
- Means: Second and third terms (b and c)
Fundamental Property
Product of extremes = Product of means
If a:b::c:d, then a×d = b×c
Example
Find x if x:6::5:15
Solution:
- Using the property: x × 15 = 6 × 5
- 15x = 30
- x = 30 ÷ 15 = 2
Answer: x = 2
Continued Proportion
Definition
Three quantities a, b, c are in continued proportion if a:b = b:c, which means b² = ac.
Properties
- The middle term is called the mean proportional
- If a:b::b:c, then b is the mean proportional between a and c
Example
Find the third proportional to 4 and 8
Solution:
- Let third proportional be x
- Then 4:8::8:x
- 4 × x = 8 × 8
- 4x = 64
- x = 16
Answer: The third proportional is 16.
Difference Between Ratio, Proportion, and Unitary Method Explained Simply
| Aspect | Ratio | Proportion | Unitary Method |
| Definition | Comparison of two quantities | Equality of two ratios | Finding value through one unit |
| Expression | a:b or a/b | a:b::c:d | Value of 1 unit → value of n units |
| Key Property | Shows relative size | Product of extremes = Product of means | Uses multiplication/division |
| Example | Boys:Girls = 3:2 | 3:2::6:4 | 5 pens cost ₹25 → 1 pen costs ₹5 |
| Use Case | Comparing quantities | Solving for unknown terms | Practical calculation problems |
When to Use Each
- Ratio: When comparing two quantities (speed comparison, mixture problems)
- Proportion: When four quantities are related and you need to find an unknown
- Unitary Method: When solving real-world problems involving rates, prices, or scaling
Practice Questions on Ratio and Proportion for Class 6 to 8
Level 1: Basic Questions
- Find the ratio of 48 minutes to 1 hour in simplest form.
- If 12:x::3:5, find the value of x.
- The ratio of boys to girls in a class is 5:3. If there are 15 boys, how many girls are there?
- Divide 63 in the ratio 7:2.
- Find three equivalent ratios of 2:5.
Level 2: Intermediate Questions
- A bus travels 126 km in 3 hours and a train travels 315 km in 5 hours. Find the ratio of their speeds.
- Two numbers are in the ratio 11:12. If their sum is 460, find the numbers.
- If x:y = 2:3, find the value of (3x + 2y):(9x + 5y).
- The cost of 1 dozen eggs is ₹30. Find the cost of 8 eggs.
- Find the fourth proportional to 25, 100, and 40.
Level 3: Advanced Questions
- If 2x + 3y:3x + 5y = 18:29, find x:y.
- The ratio of male to female workers in a textile mill is 5:3. If there are 115 male workers, find the number of female workers.
- Sushil's salary for 9 months is ₹21,000. Find his salary for 15 months.
- Show that a, b, c are in proportion if (6a + 7b):(6c + 7d)::(6a - 7b):(6c - 7d).
- If b is the mean proportional between a and c, prove that abc(a + b + c)³ = (ab + bc + ca)³.
Tips and Shortcuts for Unitary Method in Competitive Exams
Shortcut 1: Direct Multiplication for Simple Problems
Instead of dividing first, multiply directly:
- If 5 items cost ₹100, then 8 items cost = (100/5) × 8 = ₹160
- Quick formula: (New quantity/Old quantity) × Old value
Shortcut 2: Cross-Multiplication for Proportions
For a:b::c:d, directly use: a×d = b×c
This saves time in finding unknown terms.
Shortcut 3: Percentage Method for Ratio Problems
Convert ratios to percentages for easier calculation:
- Ratio 3:2 means first part is 3/(3+2) = 60%, second is 40%
Shortcut 4: Inverse Proportion Quick Formula
For inverse proportion: a₁ × b₁ = a₂ × b₂
Directly solve: b₂ = (a₁ × b₁)/a₂
Shortcut 5: Speed Calculation
- Speed = Distance/Time
- If doubling time, distance also doubles (at same speed)
- Use this for quick mental calculations
Time-Saving Tips
- Memorize common ratios: 1:2, 2:3, 3:4, 4:5, etc.
- Practice HCF quickly for simplifying ratios
- Unit conversion chart: Keep mental notes of ml↔L, cm↔m, paise↔rupees
- Check answer reasonableness: If buying more, cost should increase
- Use estimation: Round numbers for quick verification
Common Mistakes to Avoid
- Forgetting to convert units before comparing
- Reversing the ratio order
- Dividing instead of multiplying (or vice versa)
- Not simplifying the final ratio
- Mixing up direct and inverse proportions
Formula
| Formula Name | Mathematical Representation | Explanation |
| Unitary Method (More) | Value of n units = (Value of 1 unit) × n | To get more, multiply |
| Unitary Method (Less) | Value of 1 unit = (Value of n units) ÷ n | To get less, divide |
| Ratio as Fraction | a:b = a/b | Ratio expressed as fraction |
| Equivalent Ratio | a:b = (a×k):(b×k) or (a÷k):(b÷k) | Multiply/divide both terms by same number |
| Proportion Property | If a:b::c:d, then a×d = b×c | Product of extremes = Product of means |
| Mean Proportional | If a:b::b:c, then b² = ac | b is mean proportional between a and c |
| Fourth Proportional | If a:b::c:x, then x = (b×c)/a | Finding fourth term in proportion |
| Third Proportional | If a:b::b:x, then x = b²/a | Finding third term in continued proportion |
| Inverse Proportion | a₁ × b₁ = a₂ × b₂ | Product remains constant |
| Ratio Comparison | Convert to same denominator, compare numerators | LCM method for comparison |
Conclusion
Mastering the unitary method, ratios, and proportions is essential for building strong mathematical foundations. These concepts are not just academic—they're practical tools used daily in shopping, cooking, traveling, and countless other situations. By understanding the principles, practicing regularly, and applying the shortcuts provided, students can excel in both classroom assessments and competitive examinations.
Main Points
Unitary method simplifies complex calculations by finding unit values first
Ratios help compare quantities meaningfully
Proportions establish relationships between four quantities
Practice with diverse problems builds confidence and speed
Real-world applications make learning meaningful and memorable
Note for Students: This guide aligns with the CBSE Class 6 Mathematics notes curriculum and provides comprehensive coverage of the Unitary Method, Ratio, and Proportion chapter. Use this resource alongside your textbook for thorough preparation.
Frequently Asked Questions
The unitary method is a technique of finding the value of a single unit first, then calculating the required number of units. It's used in daily life for shopping calculations, speed-distance problems, work-time calculations, and converting currencies. The method is based on finding the unit rate first.
A ratio is a comparison between two quantities (like 3:4), while a proportion is an equation stating that two ratios are equal (like 3:4::6:8). Ratios compare two values, whereas proportions involve four values where the product of extremes equals the product of means.
To simplify a ratio, find the HCF (Highest Common Factor) of both terms and divide both by the HCF. For example, to simplify 42:63, find HCF(42,63) = 21, then divide: 42÷21 = 2 and 63÷21 = 3, giving the simplest form 2:3.
No, ratios can only be formed between quantities with the same unit. Before forming a ratio, you must convert both quantities to the same unit. For example, to find the ratio of 2 metres to 50 cm, convert to 200 cm to 50 cm = 4:1.
In direct proportion, when one quantity increases, the other also increases proportionally (like distance and fuel). In inverse proportion, when one quantity increases, the other decreases (like number of workers and time taken). The key is understanding the relationship between variables.
In a proportion a:b::c:d, the first and fourth terms (a and d) are called extremes, while the second and third terms (b and c) are called means. The fundamental property is: product of extremes (a×d) = product of means (b×c).
Mean proportional is the middle term when three quantities are in continued proportion. If a:b::b:c, then b is the mean proportional between a and c. To find it: b = √(a×c). For example, the mean proportional between 4 and 9 is √(4×9) = √36 = 6.
Follow these steps:
- Identify what is given and what needs to be found
- Find the value of one unit by dividing
- Find the required value by multiplying.
Always check if it's direct or inverse proportion. Practice with real-world examples like shopping, speed, or work problems.
Multiplying or dividing both terms of a ratio by the same non-zero number gives an equivalent ratio with the same value. This property helps in comparing ratios (by making denominators equal) and solving proportion problems. It's similar to equivalent fractions.
Common errors include: (1) Not converting to same units before finding ratio, (2) Reversing the order of terms, (3) Confusing direct and inverse proportion, (4) Forgetting to simplify final answers, (5) Calculation errors in cross-multiplication. Always verify your answer makes practical sense.