Class 11 students can access well-explained RD Sharma Solutions for Chapter 11 – Trigonometric Equations to strengthen their preparation for school exams and board assessments. This chapter introduces the important topic of Trigonometric Equations, which are mathematical equations that include trigonometric functions like sine, cosine, tangent, etc., with unknown angle values.
These solutions are carefully prepared by subject matter experts to help students understand the key concepts easily and develop confidence in solving problems. The solutions are structured in a step-by-step manner, making it easier for students to improve their conceptual clarity and mathematical skills.
For added convenience, Class 11 Chapter 11 Trigonometric Equations RD Sharma Solutions PDF links are provided, allowing students to access the study material anytime and practice effectively.
RD Sharma Solutions Class 11 Maths Trigonometric Equations : Highlights
Chapter 11 consists of a single comprehensive exercise that focuses on solving different types of trigonometric equations. The RD Sharma Solutions offer accurate, detailed answers to every question in this exercise. By solving these problems regularly, students can build confidence and enhance their problem-solving speed, which is crucial during board examinations.
RD Sharma Solutions Class 11 Maths Chapter 11
- Important Definitions Related to Trigonometric Equations
- General Solutions for Standard Trigonometric Equations
- Methods to Solve Trigonometric Equations in Special Cases
RD Sharma Solutions Class 11 Maths Chapter 11 - Trigonometric Equations Question with Answers
Solve: sin θ = 0, for θ ∈ [0, 2π]
Solution: θ = 0, π, 2π
Solve: cos θ = 0, for θ ∈ [0, 2π]
Solution: θ = π/2, 3π/2
Solve: tan θ = 0, for θ ∈ [0, 2π]
Solution: θ = 0, π, 2π
Find general solution of sin θ = 1.
Solution: θ = 2nπ + π/2
Find general solution of cos θ = 1.
Solution: θ = 2nπ
Find general solution of sin θ = -1.
Solution: θ = 3π/2 + 2nπ
Solve: cos θ = -1.
Solution: θ = π + 2nπ
Solve: sin θ = sin α.
Solution: θ = nπ + (-1)n α
Solve: cos θ = cos α.
Solution: θ = 2nπ ± α
Solve: tan θ = tan α.
Solution: θ = nπ + α
Find θ ∈ [0, 2π] such that sin θ = √3/2.
Solution: θ = π/3, 2π/3
Solve: cos θ = 1/2, for θ ∈ [0, 2π].
Solution: θ = π/3, 5π/3
Solve: tan θ = 1, for θ ∈ [0, 2π].
Solution: θ = π/4, 5π/4
Solve: sin 2θ = 0, θ ∈ [0, 2π].
Solution: θ = 0, π/2, π, 3π/2, 2π
Find general solution of cos 2θ = 0.
Solution: θ = (2n + 1)π/4
Solve: sin θ = -√2/2, θ ∈ [0, 2π].
Solution: θ = 5π/4, 7π/4
Find θ ∈ [0, 2π] such that cos θ = -√3/2.
Solution: θ = 5π/6, 7π/6
Solve: sin²θ = 1/4.
Solution: θ = π/6, 5π/6, 7π/6, 11π/6
Solve: cos²θ = 1/4.
Solution: θ = π/3, 5π/3, 2π/3, 4π/3
Solve: tan²θ = 3.
Solution: θ = π/3, 2π/3, 4π/3, 5π/3
Solve: 2sin²θ - 1 = 0.
Solution: θ = π/4, 3π/4, 5π/4, 7π/4
Solve: cos²θ - sin²θ = 0.
Solution: θ = π/4, 3π/4, 5π/4, 7π/4
Solve: sin θ + cos θ = 0, θ ∈ [0, 2π].
Solution: θ = 3π/4, 7π/4
Solve: tan θ - √3 = 0, θ ∈ [0, 2π].
Solution: θ = π/3, 4π/3
Solve: sin 3θ = 0, θ ∈ [0, 2π].
Solution: θ = 0, π/3, 2π/3, π, 4π/3, 5π/3, 2π
Benefits of Solving RD Sharma Class 11 Trigonometric Equations
1. Strengthens Fundamental Understanding: Solving RD Sharma’s trigonometric equation problems helps students build a strong foundation in the basic principles of trigonometric identities and equations. It clarifies essential concepts like general solutions, principal solutions, and angle relationships, making it easier to tackle complex problems in later classes.
2. Improves Step-by-Step Problem-Solving Skills: RD Sharma provides detailed and structured solutions. By practicing these, students learn how to logically break down complex equations into simple, manageable steps. This stepwise learning improves their analytical thinking and exam-solving techniques.
3. Covers Comprehensive Types of Questions: The book includes a wide variety of question types, from basic conceptual problems to higher-order thinking skills (HOTS). This ensures students are well-prepared not only for school exams but also for competitive exams like JEE, NEET, and other entrance tests.
4. Boosts Accuracy and Speed: Regular practice of RD Sharma exercises, especially in trigonometric equations, helps students improve their speed and accuracy in calculations. Timely practice reduces common errors in signs, angles, and quadrant-related confusions.
5. Confidence Booster Before Exams: By solving chapter-wise and exercise-wise problems, students gain more confidence. RD Sharma offers a systematic progression from easy to difficult questions, which helps reduce exam anxiety and prepares students to handle tricky problems with ease.
6. Develops Exam Writing Skills: The stepwise solutions guide students on how to write answers neatly and clearly, which is crucial during board exams. Students learn how to present answers logically, improving their chances of securing full marks.
7. Aligns with NCERT and CBSE Curriculum: RD Sharma is designed according to the CBSE and NCERT guidelines, making it an ideal resource for Class 11 final exams and Class 12 preparations. It ensures that students do not miss out on any important syllabus topics.
8. Helps in Competitive Exam Preparation: Since trigonometry is a key component of many competitive exams, practicing RD Sharma’s problems sharpens the student’s skills for future academic challenges, including engineering, medical, and state-level entrance exams.
Frequently Asked Questions
Chapter 11 focuses on solving trigonometric equations—equations that include trigonometric functions with unknown angles. It introduces general and principal solutions, and explores equations in various formats
There is one main exercise in Chapter 11. However, each question may have multiple sub-parts that cover a wide range of trigonometric problems.
The solutions cover:
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Basic equations (e.g., sin x = sin α, cos x = cos α),
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Equations with multiple angles (sin 2x, cos 3x, etc.),
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Special or transformed forms using identities and substitution techniques
Yes. RD Sharma offers general solution forms such as:
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sin x = sin α ⇒ x = nπ + (–1)^n α,
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cos x = cos α ⇒ x = 2nπ ± α,
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tan x = tan α ⇒ x = nπ + α,
covering the complete set of possible answers
Absolutely. Expert-verified solutions are designed for step-by-step learning, boosting accuracy and speed—ideal for board exams and entrance tests like JEE/NEET
These solutions are created by experienced educators and subject matter experts from reputed platforms like Infinity Learn, ensuring clarity and correctness
Yes. Many solutions include tips, tricks, and identity-based shortcuts to efficiently solve complicated equations and improve problem-solving speed