| Board | CBSE |
| Textbook | NCERT |
| Class | Class 6 |
| Subject | Maths |
| Chapter | Questions for Chapter 2 Whole Numbers |
| Chapter Name | Chapter 2 Whole Numbers |
| Category | Worksheets |
Extra Questions with solutions for Chapter 2 Whole Numbers Class 6 Maths
This page consists of extra questions with answers for Chapter 2 Whole Numbers prepared by experts. Each worksheet for Chapter 2 Whole Numbers of class 6 Maths consists of Extra questions in the form of MCQ and subjective questions based on Chapter 2 Whole Numbers with detailed explanations and solutions. All the Important questions for Chapter 2 Whole Numbers required for practice are covered. Do solve NCERT questions with the help of NCERT Solutions for class 6 Maths and more worksheets check out worksheets for class 6 Maths.
Extra Questions for Chapter 2 Whole Numbers
Question-1.The difference between the larges 5-digits number and the smallest 5-digits number is
(a)90,000 (b)89, 999
(c)109, 999 (d)None of these
Answer.(b) 9 9 9 9 9
(-) 1 0 0 0 0
8 9 9 9 9
Question-2.The property represented by a × (b + c) = a × b + a × c is
(a) Commutative Property (b) Associative Property
(c) Distributive Property (d) None of these
Answer-(c) It is the general form of Distributive Property.
Question-3. The product of two Odd Numbers is
(a) an even number (b) an odd number
(c) cannot be determined (d) None of these
Answer-(b) The product of two odd numbers is an odd number.
Question-4. What least number should be added to 1330 to get a number exactly divisible by 43?
(a) 46 (b) 1
(c) 3 (d) 7
Answer-(c)When 1330 is divided by 43, the remainder comes to 40.
(c) the required no = 1330 + (43 – 40) = 1333
Question-5. What least number must be subtracted from 13,601 to get a number exactly divisible by 87?
(a) 25 (b) 29
(c) 27 (d) 23
Answer-(b)When divided by given no. remainders come 29.
Hence required no. = 13,601 – 29 = 13,572
Find below a pdf of additional questions and answers for Chapter 2 Whole Numbers CBSE Class 6 Maths
