JEE Main Marks Vs Percentile 2025
Candidates preparing for JEE Main 2025 can refer to this detailed guide to understand the expected marks vs percentile distribution. The percentile scores for JEE Main 2025 will be calculated based on the candidates' performance in the exam, using a formula provided by the National Testing Agency (NTA). The results for JEE Main Marks vs Percentile 2025 will be released on the official NTA JEE Main website, along with the final results. NTA is expected to conduct the first session of JEE Main 2025 in the last week of January, and the application form will likely be available in November 2024.
JEE Main Marks vs Percentile 2025 (Expected)
Below is the expected JEE Main Marks vs Percentile table for 2025, based on data from previous years. This table will help candidates estimate their percentile based on their marks. For example, those scoring between 280-284 marks are expected to secure a percentile of 99.99 in JEE Main 2025.
Marks out of 300 | Rank | Percentile |
288-294 | 20-11 | 99.99826992 - 99.99890732 |
280-284 | 44-22 | 99.99617561 – 99.99790569 |
270-279 | 107-63 | 99.99034797 – 99.99417236 |
252-268 | 522-106 | 99.95228621-99.99016586 |
231-249 | 1385-546 | 99.87388626-99.95028296 |
215-230 | 2798-1421 | 99.74522293-99.87060821 |
202-214 | 4666-2862 | 99.57503767-99.73930423 |
190-200 | 6664-4830 | 99.39319714-99.56019541 |
175-189 | 10746-7151 | 99.02150308-99.3487614 |
161-174 | 16163-11018 | 98.52824811-98.99673561 |
149-159 | 21145-16495 | 98.07460288-98.49801724 |
132-148 | 32826-22238 | 97.0109678-97.97507774 |
120-131 | 43174-33636 | 96.0687115-96.93721175 |
110-119 | 54293-44115 | 95.05625037-95.983027 |
102-109 | 65758-55269 | 94.01228357-94.96737888 |
95-101 | 76260-66999 | 93.05600452-93.89928202 |
89-94 | 87219-78111 | 92.05811248-92.88745828 |
79-88 | 109329-90144 | 90.0448455-91.79177119 |
62-87 | 169542-92303 | 84.56203931-91.59517945 |
41-61 | 326517-173239 | 70.26839007-84.22540213 |
1-42 | 1025009-334080 | 6.66590786-69.5797271 |
Also Check: JEE Main 2025 Eligibility Criteria
Why is the JEE Main Result in Percentile Form?
The JEE Main exam is conducted over several shifts with different question papers. Despite efforts to keep all papers equivalent in difficulty, there may be slight variations. To ensure fairness, NTA uses a normalization procedure to adjust scores based on the difficulty level of each session. This ensures that no candidate is unfairly advantaged or disadvantaged due to the variation in question paper difficulty. The percentile score shows a candidate's performance relative to other test takers. For example, a 99 percentile means that 99% of the candidates scored below that individual.
JEE Main Normalization Process
The normalization formula ensures that scores from different shifts are comparable. It uses the following formula for calculating the percentile for each subject (Maths, Physics, Chemistry) and the overall score:
- Total JEE Main Percentile (T1P) = (100 x Number of candidates in a particular shift with a raw score equal to or less than T1 score) / Total number of candidates in that shift
- Mathematics JEE Main Percentile (M1P) = (100 x Number of candidates in a shift with a raw score equal to or less than in Mathematics) / Total number of candidates in that shift
- Physics JEE Main Percentile (P1P) = (100 x Number of candidates in a shift with a raw score equal to or less than in Physics) / Total number of candidates in that shift
- Chemistry JEE Main Percentile (C1P) = (100 x Number of candidates in a shift with a raw score equal to or less than in Chemistry) / Total number of candidates in that shift
Tie-Breaker Rules
If two or more candidates achieve the same percentile score, the following tie-breaker rules are applied:
- Candidates with higher marks in Mathematics are given a higher rank.
- If still tied, candidates with higher Physics marks are ranked higher.
- If still tied, candidates with higher Chemistry marks are ranked higher.
- If the tie persists, older candidates are ranked higher.
Also Check: JEE Main 2025 Admit Card
Number of Candidates Appeared in JEE Main 2024
The table below shows the number of candidates who appeared for the JEE Main 2024 exam across different shifts. This data helps in understanding the scale of competition for the upcoming exam.
Exam Date | Shift | Female Candidates | Male Candidates | Total Candidates |
Jan 27 | 1 | 39816 | 82371 | 122187 |
Jan 27 | 2 | 39613 | 85659 | 125272 |
Jan 29 | 1 | 39734 | 82589 | 122323 |
Jan 29 | 2 | 40759 | 84089 | 124848 |
Jan 30 | 1 | 41037 | 80761 | 121798 |
Jan 30 | 2 | 40092 | 80936 | 121028 |
Jan 31 | 1 | 41705 | 83389 | 125094 |
Jan 31 | 2 | 39829 | 81088 | 120917 |
Feb 1 | 1 | 39968 | 81237 | 121205 |
Feb 1 | 2 | 38384 | 78568 | 116952 |
FAQs
A good score for JEE Main 2025 would be around 250 or more. To secure a seat in NITs or IITs, a percentile between 85 and 95 is generally considered sufficient. However, you typically need to rank within the top 15,000 to 20,000 to be eligible for admission to these institutes.
Yes, according to the 2025 JEE brochure, IITs have reinstated the requirement of 75% marks in Class 12 board exams for admissions to NITs, IIITs, and CFTIs.
To perform well in the JEE exam, students should aim to study for at least 8 to 10 hours a day for a few months before the exam. It’s important to balance your study time with breaks to avoid burnout and make sure you’re studying effectively.
It’s a misconception that taking a drop year is a waste of time. In reality, around 50 to 60 percent of the students who drop a year for extra preparation successfully secure a seat in IITs.
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