The Unitary Method is a very important and easy topic in Class 7 Maths. In our daily life, we often calculate the cost of many items based on the price of one item. For example, if the cost of 1 pencil is ₹5, then the cost of 10 pencils is ₹50. This method of first finding the value of one unit and then using it to find the value of multiple units (or vice versa) is called the unitary method. RD Sharma’s Class 7 Chapter 10 – Unitary Method helps students understand this concept step-by-step with simple problems and clear explanations. The chapter begins by explaining how to find the value of a single unit from multiple units, and then how to find the value of many units from a single unit. It also shows how the unitary method is used in real-life situations like shopping, traveling, and cooking. This chapter helps build strong mathematical thinking. It not only improves calculation skills but also helps students solve word problems easily. Students will learn how to deal with quantities related to time, speed, distance, weight, cost, and more.
Do Check: RD Sharma Solutions for Class 7 Maths
The RD Sharma solutions for this chapter offer well-structured answers to all the textbook questions. Each solution is explained in simple steps so that students can understand the logic behind every answer. These solutions are useful for self-study and for clearing doubts quickly. By practicing regularly, students can gain full marks in unitary method questions in exams.
Download RD Sharma Solutions for Class 7 Maths Chapter 10 Unitary Method PDF Here
You can download the RD Sharma Solutions for Class 7 Maths Chapter 10 – Unitary Method PDF from here and study anytime, anywhere. This PDF contains clear, step-by-step answers to all the questions in the chapter. It is a helpful guide for students who want to understand the unitary method in a simple way. Whether you're revising for exams or just practicing problems, this PDF will make your learning easier. You can save it on your phone, tablet, or computer and use it whenever you need help with homework or revision.
Access Answers to RD Sharma Solutions for Class 7 Maths Chapter 10 Unitary Method
Q1. Cost of 35 chocolates
If 20 chocolates cost Rs 320, then:
Cost of 1 chocolate = 320 ÷ 20 = Rs 16
Cost of 35 chocolates = 16 × 35 = Rs 560
Q2. Cost of 50 meters of cloth
If 40 meters of cloth cost Rs 200, then:
Cost of 1 meter = 200 ÷ 40 = Rs 5
Cost of 50 meters = 5 × 50 = Rs 250
Q3. Distance car travels on 14 litres
If 36 litres of petrol allows a car to travel 522 km, then:
Distance per litre = 522 ÷ 36 = 14.5 km
Distance for 14 litres = 14.5 × 14 = 203 km
Q4. Train fare for 360 km
If fare for 900 km is Rs 280, then:
Fare per km = 280 ÷ 900
Fare for 360 km = (280 ÷ 900) × 360 = Rs 112
Q5. Time to fill 4 oil tankers
If 6 tankers are filled in 4.5 hours (or 9/2 hours), then:
Time for 1 tanker = (9 ÷ 12) = 3/4 hours
Time for 4 tankers = (3/4) × 4 = 3 hours
Q6. Monthly salary
If 3/4 of salary is Rs 600, then:
Full salary = 600 × (4 ÷ 3) = Rs 800
Q7. Tables bought for Rs 51450
If 32 tables cost Rs 23520, then:
Tables per rupee = 32 ÷ 23520
Tables for Rs 51450 = (32 ÷ 23520) × 51450 = 70 tables
Q8. Land needed for 225 quintals of wheat
If 6 hectares give 280 quintals, then:
Land per quintal = 6 ÷ 280
Land for 225 quintals = (6 ÷ 280) × 225 = 4 23/28 hectares
Q9. Cost of 36 post cards and how many for Rs 45
If 15 postcards cost Rs 2.25, then:
Cost of 1 = 2.25 ÷ 15 = Rs 0.15
Cost of 36 = 0.15 × 36 = Rs 5.40
Cards per rupee = 15 ÷ 2.25 = 6.67
Cards for Rs 45 = 6.67 × 45 = 300 cards
Q10. Cost of 120 km rail journey
If 75 km costs Rs 215, then:
Cost per km = 215 ÷ 75
Cost of 120 km = (215 ÷ 75) × 120 = Rs 344
Q11. Sales tax on Rs 150
If Rs 60 has tax of Rs 4.20, then:
Tax per rupee = 4.20 ÷ 60 = Rs 0.07
Tax on Rs 150 = 0.07 × 150 = Rs 10.50
Q12. Cost of 65 packets of 10 pencils each
52 packets of 12 pencils = 52 × 12 = 624 pencils
Cost of 624 pencils = Rs 499.20
Cost per pencil = 499.20 ÷ 624 = Rs 0.80
65 packets of 10 pencils = 65 × 10 = 650 pencils
Cost of 650 pencils = 0.80 × 650 = Rs 520