Understanding the concepts of Ratio and Proportion is a key part of learning mathematics in Class 7. These ideas are not just useful in solving math problems, but also in everyday life. Whether it's comparing prices, calculating speed, or dividing things fairly, ratios and proportion play a big role. Chapter 9 of the RD Sharma Class 7 Maths textbook covers this topic in a step-by-step and simple manner, helping students build a strong foundation. The chapter begins by explaining the meaning of a ratio—a way to compare two quantities of the same kind using division. For example, if there are 2 apples and 3 oranges, we can say the ratio of apples to oranges is 2:3. The chapter then moves on to proportion, which tells us when two ratios are equal. For instance, 2:3 and 4:6 are in proportion because both represent the same relationship.
RD Sharma’s solutions for this chapter make it easier for students to understand each concept clearly. The solutions offer detailed explanations, step-by-step methods, and a variety of solved examples. These help learners practice different types of questions and gain confidence. Each exercise is carefully solved, making it easier to revise and score well in exams. The solutions are especially helpful for students who want to practice regularly and improve their problem-solving skills. Whether you're preparing for a school test or just want to strengthen your math basics, these solutions are a valuable learning tool.
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Download RD Sharma Solutions for Class 7 Maths Chapter 9 Ration And Proportion PDF Here
You can download the RD Sharma Solutions for Class 7 Maths Chapter 9 – Ratio and Proportion PDF from here easily. This PDF includes clear and step-by-step solutions for all the questions in the chapter. It is perfect for students who want to understand the topic better and practice regularly. The PDF format makes it simple to study anytime, even without the internet. Whether you're preparing for exams or just revising the chapter, this free downloadable file will help you learn and solve problems quickly.
Access Answers to RD Sharma Solutions for Class 7 Maths Chapter 9 Ration And Proportion
This chapter helps students understand how to compare numbers using ratios and solve problems based on proportions. The questions below are solved using easy steps and simple methods to help you learn better.
Q1. If x : y = 3 : 5, find the ratio (3x + 4y) : (8x + 5y)
Solution:
x/y = 3/5 → x = 3y/5
Substitute in the ratio:
(3x + 4y) : (8x + 5y) = (3 × 3y/5 + 4y) : (8 × 3y/5 + 5y)
= (9y/5 + 4y) : (24y/5 + 5y)
= (29y/5) : (49y/5) = 29 : 49
Q2. If x : y = 8 : 9, find the ratio (7x - 4y) : (3x + 2y)
Solution:
x/y = 8/9 → x = 8y/9
Substitute in the ratio:
(7x - 4y) : (3x + 2y) = (56y/9 - 4y) : (24y/9 + 2y)
= (20y/9) : (42y/9) = 20 : 42 = 10 : 21
Q3. Two numbers are in the ratio 6 : 13 and their LCM is 312. Find the numbers.
Solution:
Let the numbers be 6x and 13x.
LCM = 78x = 312 → x = 4
So, the numbers are 6x = 24 and 13x = 52
Q4. Two numbers are in the ratio 3 : 5. If 8 is added to both, the new ratio becomes 2 : 3. Find the numbers.
Solution:
Let numbers be 3x and 5x.
(3x + 8)/(5x + 8) = 2/3
Solve for x → x = 8
Numbers: 3x = 24, 5x = 40
Q5. What should be added to both terms of 7 : 13 to make the ratio 2 : 3?
Solution:
Let the number be x.
(7 + x)/(13 + x) = 2/3 → Solve for x → x = 5
Q6. Three numbers are in the ratio 2 : 3 : 5 and their total is 800. Find the numbers.
Solution:
Total parts = 2 + 3 + 5 = 10
First = 160, Second = 240, Third = 400
Q7. Ages of two persons are in ratio 5 : 7. Eighteen years ago, their ratio was 8 : 13. Find their present ages.
Solution:
Let ages be 5x and 7x.
(5x - 18)/(7x - 18) = 8/13 → Solve for x = 10
Ages = 50 and 70 years
Q8. Two numbers are in the ratio 7 : 11. If 7 is added to both, ratio becomes 2 : 3. Find the numbers.
Solution:
Let numbers be 7x and 11x.
(7x + 7)/(11x + 7) = 2/3 → Solve for x = 7
Numbers: 49 and 77
Q9. Two numbers are in the ratio 2 : 7 and their sum is 810. Find the numbers.
Solution:
Total parts = 9
First = (2/9)×810 = 180
Second = (7/9)×810 = 630
Q10. Divide Rs. 1350 between Ravish and Shikha in the ratio 2 : 3.
Solution:
Total parts = 5
Ravish = (2/5)×1350 = Rs. 540
Shikha = (3/5)×1350 = Rs. 810
Q11. Divide Rs. 2000 among P, Q, and R in the ratio 2 : 3 : 5.
Solution:
Total parts = 10
P = Rs. 400, Q = Rs. 600, R = Rs. 1000
Q12. Boys and girls in a school are in the ratio 7 : 4. If total students = 550, find number of boys and girls.
Solution:
Total parts = 11
Boys = (7/11)×550 = 350
Girls = (4/11)×550 = 200
Q13. Monthly income to savings ratio of a family is 7 : 2. If savings = Rs. 500, find income and spending.
Solution:
Savings = 2x = Rs. 500 → x = 250
Income = 7x = Rs. 1750
Expenses = 1750 - 500 = Rs. 1250