Simple Interest is one of the most basic and important topics in mathematics, especially useful in our day-to-day life. It helps us understand how money grows over time when it is borrowed or invested. Whether it’s a bank loan, a savings deposit, or a money-lending transaction, simple interest plays a key role. That’s why it is important for students to understand this concept clearly. The RD Sharma Mathematics book for Class 13 provides a well-structured and easy-to-understand approach to learning Simple Interest. It explains the basic formula, how to calculate interest, principal amount, rate, and time with step-by-step examples. But sometimes, students may still find it hard to solve all the questions on their own. This is where RD Sharma Solutions for Class 13 Simple Interest comes in handy. These solutions are prepared by experts to make learning simple and effective. Each question from the RD Sharma textbook is solved in a clear, step-by-step method. This helps students understand not just the answer but also the logic behind it. Whether you are preparing for exams or just revising your concepts, these solutions act as a perfect guide.
The language used in the solutions is simple so that every student can understand it easily. It also includes shortcut methods, important tips, and tricks to solve problems faster. Practicing these solutions regularly can help students build confidence and improve their performance in exams.
Also Check: RD Sharma Solutions for Class 7 Maths
Download RD Sharma Solutions for Class 7 Maths Chapter 13 Simple Interest PDF Here
You can download the RD Sharma Solutions for Class 7 Maths Chapter 13 – Simple Interest PDF from here to study anytime, anywhere. This PDF has all the answers to the questions from the textbook, explained in a simple and clear way. It is very helpful for students who want to understand the topic better and score good marks in exams. You can use it for practice, revision, or homework help. The step-by-step solutions make it easy to follow and learn. Just click the download link and start learning at your own pace!
Access Answers to RD Sharma Solutions for Class 7 Maths Chapter 13 Simple Interest
Q1. Find the simple interest for the following cases:
Ques: A person lends Rs. 2000 at a rate of 5% per annum for 5 years. What will be the simple interest?
Answer:
Principal (P) = Rs. 2000
Rate of Interest (R) = 5% per annum
Time (T) = 5 years
Using the formula SI = (P × R × T) / 100
SI = (2000 × 5 × 5) / 100 = Rs. 500
Ques: Calculate the simple interest on Rs. 500 at a rate of 12.5% per annum for 4 years.
Answer:
P = Rs. 500, R = 12.5%, T = 4 years
SI = (500 × 12.5 × 4) / 100 = Rs. 250
Ques: Find the interest on Rs. 4500 for 6 months at a yearly rate of 4%.
Answer:
Time = 6 months = 0.5 years
SI = (4500 × 0.5 × 4) / 100 = Rs. 90
Ques: Calculate the interest for Rs. 12000 at 18% per annum for 4 months.
Answer:
Time = 4 months = 1/3 years
SI = (12000 × 18 × 1/3) / 100 = Rs. 720
Ques: How much simple interest is earned on Rs. 1000 at 10% per annum for 73 days?
Answer:
Time = 73/365 years
SI = (1000 × 10 × 73) / (100 × 365) = Rs. 20
Q2. A sum of Rs. 500 is invested at 8% per annum for 4 years. Calculate the interest and the total amount to be received after 4 years.
Answer:
SI = (500 × 8 × 4) / 100 = Rs. 160
Total Amount = 500 + 160 = Rs. 660
Q3. A person lends Rs. 400 at 5% simple interest for 2 years. What is the interest amount?
Answer:
SI = (400 × 5 × 2) / 100 = Rs. 40
Q4. Calculate the interest earned on Rs. 400 at 6% per annum after 3 years.
Answer:
SI = (400 × 6 × 3) / 100 = Rs. 72
Q5. A person deposits Rs. 25000 in a firm offering 20% annual interest. How much income will he earn in one year?
Answer:
SI = (25000 × 20 × 1) / 100 = Rs. 5000
Q6. A loan of Rs. 8000 is taken at 8% interest per year for 4.5 years. What amount must be repaid?
Answer:
Time = 4.5 years = 9/2 years
SI = (8000 × 8 × 9) / (2 × 100) = Rs. 2880
Total = 8000 + 2880 = Rs. 10880
Q7. Rakesh lends Rs. 8000 at 15% for 5 years and borrows Rs. 6000 at 12% for 3 years. Find his overall gain or loss.
Answer:
SI (Lent) = (8000 × 15 × 5) / 100 = Rs. 6000
SI (Borrowed) = (6000 × 12 × 3) / 100 = Rs. 2160
Net Gain = 6000 − 2160 = Rs. 3840
Q8. Anita deposits Rs. 1000 in a bank at 5% annual interest. What will be the amount in her account after 1 year?
Answer:
SI = (1000 × 5 × 1) / 100 = Rs. 50
Total Amount = 1000 + 50 = Rs. 1050
Q9. Nalini borrows Rs. 550 at 8% per annum. She repays after 6 months. How much does she pay?
Answer:
Time = 6 months = 0.5 years
SI = (550 × 8 × 0.5) / 100 = Rs. 22
Total = 550 + 22 = Rs. 572
Q10. Rohit borrows Rs. 60000 at 9% per annum and lends it to Rohan at 10%. Both loans are for 2 years. What is Rohit’s profit?
Answer:
SI Earned = (60000 × 10 × 2) / 100 = Rs. 12000
SI Paid = (60000 × 9 × 2) / 100 = Rs. 10800
Profit = 12000 − 10800 = Rs. 1200
Q11. Romesh borrows Rs. 2000 at 2% and Rs. 1000 at 5% for 2 years. He repays Rs. 2800 and a watch. What is the cost of the watch?
Answer:
SI (Rs. 2000) = (2000 × 2 × 2) / 100 = Rs. 80
SI (Rs. 1000) = (1000 × 5 × 2) / 100 = Rs. 100
Total Debt = 2000 + 1000 + 80 + 100 = Rs. 3180
Paid = Rs. 2800
Watch Value = 3180 − 2800 = Rs. 380
Q12. Mr. Garg lends Rs. 15000: Rs. 12500 at 15% and remaining at 18%. Find the total interest in 3 years.
Answer:
SI (Rs. 12500) = (12500 × 15 × 3) / 100 = Rs. 5625
SI (Rs. 2500) = (2500 × 18 × 3) / 100 = Rs. 1350
Total Interest = Rs. 6975
Q13. Shikha deposits Rs. 2000 at 6% interest. She withdraws Rs. 700 after 1 year. What will be her final balance after 3 years?
Answer:
Year 1 SI = (2000 × 6 × 1) / 100 = Rs. 120
Total = 2120, Remaining = 2120 − 700 = Rs. 1420
SI on Rs. 1420 for 2 years = (1420 × 6 × 2) / 100 = Rs. 170.40
Final Balance = 1420 + 170.40 = Rs. 1590.40
Q14. Reema borrows Rs. 8000 at 18% per annum. After 2 years, she repays Rs. 10400 and a watch. What is the price of the watch?
Answer:
SI = (8000 × 18 × 2) / 100 = Rs. 2880
Total = 8000 + 2880 = Rs. 10880
Watch Value = 10880 − 10400 = Rs. 480
Q15. Mr. Sharma deposits Rs. 20000 at 10% for 1 year. 30% of interest is deducted as tax. Find his annual income.
Answer:
SI = (20000 × 10 × 1) / 100 = Rs. 2000
Tax = 30% of 2000 = Rs. 600
Net Income = 2000 − 600 = Rs. 1400