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Chapter-Genomics and Bioinformatics

Board CBSE
Textbook NCERT
Class Class 12
Subject Biotechnology
Chapter Chapter-Genomics and Bioinformatics
Chapter Name Genomics And Bioinformatics
Category CUET (Common University Entrance Test) UG

Important MCQ-Based Questions for CUET Biotechnology chapter-Genomics And Bioinformatics

This page consists of Important MCQ questions from chapter-Genomics And Bioinformatics uploaded as per the CUET syllabus and consists of a detailed explanation. Questions are prepared from the entire chapter-Genomics And Bioinformatics to give you effective revision. 

Find below MCQ-Based Questions for CUET Biotechnology chapter-Genomics And Bioinformatics

Important MCQ-based questions Biotechnology CUET chapter-Genomics And Bioinformatics Set-A

Biotechnology - MCQ on Genomics And Bioinformatics

Biotechnology - MCQ on Genomics And Bioinformatics

Class XII

Q.41 Human genome project was started in

(a) 1990

(b) 1991

(c) 1992

(d) 1993

Answer:

(a)

Exp: Human genome project was officially started on October 1,1990.

Q.42 The first sequenced genome was of

(a) Mycobacterium tuberculosis.

(b) Bacillus subtilis.

(c) Haemophilus influenzae.

(d) Drosophila melanogaster.

Answer:

(c)

Exp: The first set of whole genome sequences of the smallest genome Mycoplasma genitalium and Haemophilus influenzae.

Q.43 Celera genomics is the sequencing of

(a) human and mouse.

(b) microbes.

(c) birds.

(d) canines.

Answer:

(a)

Exp: Celera genomics is dedicated to sequencing of human and mouse genomes. Celera focuses on genetic sequencing and related technologies.

Q.44 The insert size in BAC is

(a) 10-50 kb.

(b) 80-100 kb.

(c) 120-180 kb.

(d) 200-220 kb.

Answer:

(b)

Exp: BAC vectors are used in making a genomic library in which insert size is 80-100 kb.

Q.45 ApoE gene is associated with

(a) AIDS.

(b) Alzheimer’s disease.

(c) chronic mylogenous leukemia.

(d) lymphoblastic leukemia.

Answer:

(b)

Exp: A single base difference in the ApoE gene is associated with Alzheimer’s disease.

Q.46 The location of Huntington disease is on

(a) 4th chromosome

(b) 7th chromosome

(c) 19th chromosome

(d) 20th chromosome

Answer:

(a)

Exp: Huntington is an autosomal dominant disease located on 4th chromosome.

Q.47 The technique of nick translation is developed by

(a) Thomas Roderick.

(b) J. Craig.

(c) Rigby and Paul.

(d) H. Winkler.

Answer:

(c)

Exp: Nick translation was developed by Rigby and Paul Berg in 1977.

Q.48 In comparative cDNA hybridization microarray comparison of

(a) DNA is done.

(b) rRNA is done.

(c) tRNA is done.

(d) mRNA is done.

Answer:

(d)

Exp: In comparative hybridization experiments, comparisons between the amounts of mRNA are done in two cell populations.

Q.49 Incomparative cDNA hybridization microarray the reporters are

(a) probes.

(b) cDNA.

(c) fluors.

(d) RNA.

Answer:

(c)

Exp: The reporters that are used in comparative cDNA hybridization microarray are fluorescent dyes (fluors).

Q.50 Microarrays are made from

(a) proteins.

(b) DNA.

(c) mRNA.

(d) tRNA.

Answer:

(b)

Exp: Microarrays are made from a collection of purified DNA molecules using an arraying machine.

Q.51 The number of predicted gene in E.coli is

a) 5,000.

b) 7,000.

c) 12,000.

d) 15,000.

Answer:

(a)

Exp: The number of chromosome in E.coliis 1, genome size in bp is 500,000 and the number of predicted gene is 5,000.

Q.52 Gene prediction in eukaryotes can be done by

a) SWISS- PROT.

b) PALI database.

c) GeneMark.

d) GENSCAN.

Answer:

(d)

Exp: Gene prediction is done by using programs like GeneMark (bacterial genome) and GENSCAN (eukaryotes). GENSCAN can identify introns, exons, promotor sites and poly A signals and other gene identification algorithms.

Q.53 Gene prediction in bacterial genome can be done by

a) SWISS-PROT.

b) PALI database.

c) GeneMark.

d) GENSCAN.

Answer:

(c)

Exp: Gene prediction is done by using programs like GeneMark (bacterial genome) and GENSCAN (eukaryotes).

Q.54 Prokaryotes do not have

a) DNA.

b) introns.

c) exons.

d) RNA.

Answer:

(b)

Exp: In eukaryotes the gene prediction is quite complex as the genome is the combination of exons and introns. Prokaryotes do not have introns and the gene is continuous.

Q.55 The database for ESTs is

a) dEST.

b) DSTs

c) GSTs

d) dbEST.

Answer:

(d)

Exp: EST data is used to infer expression patterns by counting the number of ESTs corresponding to each gene divided by the total number of ESTs. Millions of ESTs are deposited in a special database called dbESTs.

Q.56 The data in which one read of sequence is obtained from either end is

a) ESTs.

b) dbESTs.

c) GSTs.

d) DSTs.

Answer:

(c)

Exp: The genomic DNA refers to the nuclear DNA. The GST approach is similar to EST. One read of sequence was obtained from either end. This data is referred to as genomic sequence tags.

Q.57 All Web based tools are

a) free.

b) paid.

c) some paid, some free.

d) managed by curator.

Answer:

(a)

Exp: All Web based tools are available free e.g. BLAST, Gene level sequence etc.

Q.58 Taxonomy browser provides

a) literature.

b) answer to biological question.

c) classification of various species.

d) information on the official gene.

Answer:

(c)

Exp: The taxonomic browser provides information on taxonomic classification of various species. This database has information on over 79,000 organisms.

Q.59 Locus link carries information on

a) literature.

b) classification of various species.

c) structure of gene.

d) official gene names.

Answer:

(d)

Exp: Locus link carries information on the official gene names and other descriptive information about genes. By this one can access information on homologous genes.

Q.60 Homology is

a) similarity due to common ancestry.

b) similarity due to different ancestry.

c) similarity due to sequences.

d) similarity due to duplicated genes.

Answer:

(a)

Exp: The sequences being similar does not mean that they are homologous. Homology is defined as similarity due to common ancestry. BLAST is used for analyzing sequence information

Q.61 Duplicated genes within a genome with similarity are

a) homologs.

b) paralogs.

c) orthologs.

d) analogs.

Answer:

(b)

Exp: Duplicated genes within a genome have similarities and these are referred as paralogs. Homologues will have the same function whereas paralogs may differ in functions.

Q.62 Database of orthologs and homologs is

a) BLAST.

b) ENTREZ.

c) homoloGene.

d) Locus Link.

Answer:

(c)

Exp: Homologene is a database of orthologs and homologs for human, mouse, rat, zebrafish and cow genes represented in UniGene and Locus Link. It is very easy to find homologous relations using this database.

Q.63 RefSeq is used in

a) designing gene chip.

b) finding protein sequences.

c) finding three dimensional structure of proteins.

d) identifying the tools.

Answer:

(a)

Exp: RefSeq is a well-verified database of mRNAs and proteins of human, mouse and rat. This data is used in many cases e.g. DNA chips and describing the sequence features of human genome.

Q.64 The first attempt to compare normal haemoglobin and sickle cell haemoglobin was done by

a) J.Craig Venter.

b) Pauling.

c) V.M.Ingram.

d) Zuckerkandl.

Answer:

(c)

Exp: The history of bioinformatics began when Ingram demonstrated that there is homology between sickle cell haemoglobin and normal haemoglobin.

Q.65 The transformation of raw genomic data into organized knowledge is known as

a) structural genomics.

b) functional genomics.

c) genome annotation.

d) genome sequencing.

Answer:

(c)

Exp: Genome annotation is the attachment of biological information to the provided sequences.

Q.67 AAGCCTA and AAGCTTA are the examples of

a) SNP.

b) EST.

c) GST.

d) complementary DNA sequence.

Answer:

(a)

Exp: The two sequences are different from each by one base i.e. T in place of C. Hence it is a SNP.

Q.68 In UniGene “Uni” means

a) unique.

b) ubiquitous.

c) one.

d) useful.

Answer:

(c)

Exp: Unigene database is created to manage the redundancy in EST data. The objective is to group ESTs into sets called clusters that belongs to ‘one’ gene; here Uni means one.

Q.69 The genomic library of Plasmodium falciparum is generated by

a) restriction endonucleases.

b) DNA polymerase.

c) Mung Bean nuclease.

d) RNA polymerases.

Answer:

(c)

Exp: The genomic library of Plasmodium falciparum can be easily generated by digestion with Mnase. This library is used for gene identification in P. falciparum.

Q.70 DNA is present in

a) mitochandria.

b) ribosomes.

c) cilia.

d) endoplasmic reticulum.

Answer:

(a)

Exp: DNA is present in nucleus as well as in mitochondria and chloroplast.

Q.71. The real significance of genomics began with the introduction of

a. SNP.

b. EST.

c. GST.

d. HGP.

Answer:

(d)

Exp: The real significance of genomics began with the introduction of Human Genome Project (HGP) in the mid-1980s.

Q.72. Three dimensional structure of the proteins can be deduced by

a. functional genomics.

b. FISH technique.

c. structural genomics.

d. gene sequencing.

Answer:

(c)

Exp: Structural genomic involves high-throughput DNA sequencing followed by assembly, organization and management of DNA sequences. It also includes determination of three-dimensional structure of all the proteins.

Q.73.The principal behind DNA Microarray Technology is base pairing or hybridization between the

a. nucleotides

b. nucleosides.

c. homologs.

d. paralogs.

Answer:

(a)

Exp: This technology is DNA Microarray that promises to monitor the whole genome on a single microchip.

The principal behind DNA Microarray Technology is base pairing or hybridization between the nucleotides. Base pairing allows probes to hybridize to targets on the Microarray.

Q.74 . Biochips are also known as

a. structural genomics.

b. functional genomics.

c. fluorescent in situ hybridization.

d. DNA microarray technology.

Answer:

(d)

Exp: There are several names to DNA microarray technology such as DNA arrays, gene chips, biochips, DNA chips and gene arrays.

Q.75.DNA microarrays work on the principle of

a. EST approach.

b. bioinformatics.

c. base-pairing.

d. nick translation.

Answer:

(c)

Exp: DNA microarrays work on the principle of base pairing. Base pairing allows probes to hybridize to targets on the Microarray.

Q.76. FISH is

a. microbiology technique.

b. cytogenetics technique.

c. DNA replication technique.

d. hybridoma technique.

Answer:

(b)

Exp: FISH (Fluorescent in situ hybridization) is a cytogenetic technique that can be used to detect and localize the presence or absence of specific DNA sequences on chromosomes.

Q.77.FISH technology is useful in detecting the status of disease during

a. prophase.

b. metaphase.

c. anaphase.

d. interphase.

Answer:

(d)

Exp: FISH technology is useful in detecting the status of disease during interphase of cell division.

Q.78.Comparative cDNA hybridization microarray compare the amounts of different

a. mRNA in two cell populations.

b. chromosome in two cell populations.

c. tRNA in two cell populations.

d. ribosome in two cell populations.

Answer:

(a)

Exp: Comparative Genomic Hybridization (CGH) is a molecular- cytogenetic method for the analysis of copy number changes (gains or losses) in DNA. Comparative cDNA hybridization microarray compares the amounts of different mRNA in two cell populations.

Q.79. J.Craig Venter and co-workers used

a. GSTs.

b. FASTA.

c. ESTs.

d. BLAST.

Answer:

(c)

Exp: Expressed Sequence Tag is a unique stretch of DNA within a coding region of a gene. Craig Venter and co-workers isolated mRNA molecules and constructed cDNA molecules to create expressed sequence tags or ESTs.

Q.80. ESTs

served as a landmark for

a. gene mapping.

b. gene sequencing.

c. gene cloning.

d. gene prediction.

Answer:

(a)

Exp: Expressed Sequence Tag is a unique stretch of DNA within a coding region of a gene. It is useful for identifying full-length genes and serves as a landmark for mapping.

Q.81.The first and most commonly used tool to discover new genes is

a. Ab Initio Gene prediction.

b. homology based gene prediction.

c. systemic gene prediction.

d. Expressed Sequence Tag (ESTs).

Answer:

(b)

Exp: Gene prediction is an important problem for computational biology.Homology based Gene prediction is the first and most commonly used tool to discover new genes.

Q.82.A process that identifies genes, their regulatory sequences, and their function is called

a. structural genomics.

b. functional genomics.

c. genome annotation.

d. genome sequencing.

Answer:

(c)

Exp: Annotation is a process that identifies genes, their regulatory sequences, and their function. After a genome sequence has been obtained and checked for accuracy, the next task is to find all the genes that encode proteins.

Q.83. EMBL is

a. European Molecular Bioinformatics Limited.

b. European Molecular Biology Laboratory.

c. European Molecular Biotechnology Laboratory.

d. European Micro Bioinformatics Laboratory.

Answer:

(b)

Exp: The data library was established to collect, Organize and distribute nucleotide sequence data and related information at the European Molecular Biology Laboratory (EMBL) in 1980.

Q.84. The Protein Information Resources (PIR) was established in 1984 by the

a. NBRF.

b. EMBL.

c. EBI.

d. BIC.

Answer:

(a)

Exp: The National Biomedical Research Foundation (NBRF) as a resource to assist researchers in the identification and interpretation of protein sequence information established the Protein Information Resources (PIR) in 1984.

Q.85. The nomenclature system in bioinformatics is based on the recommendations of

a. NBRF.

b. EMBL.

c. IUPAC.

d. EBI.

Answer:

(c)

Exp: The nomenclature system in bioinformatics is based on the recommendations of International Union of Pure and Applied Chemistry (IUPAC). Different Laboratories of the world follow nomenclature system of IUPAC so that the data set can be uniformed and easy to compare.

Q.86. Building blocks of DNA are

a. nucleic acids.

b. nucleotides.

c. nucleosides.

d. nitrogenous bases.

Answer:

(b)

Exp: Nucleotides are the building blocks of DNA and each nucleotide consists of three components -

I. a nitrogenous base (purine or pyrimidine)

II. a pentose sugar and

III. a phosphate residue

Q.87. The purines are

a. Adenine and guanine

b. b. Adenine and cytocine

c. Adenine and thymine

d. Adenine and uracil

Answer:

(a)

Exp: The purines (adenine and guanine) are present in both deoxyribonucleotides and ribonucleotides

Q.88. Each nucleotide contains

a. Base + Sugar +Lipid

b. Base + Sugar + Ethanol

c. Base+ Sugar +Phosphate

d. Base + Sugar + Ketone

Answer:

c) Each nucleotide consists of three components-

A nitrogenous base (purine or pyrimidine)

A pentose sugar and

A phosphate residue

Q.89. Nucleic acid is

a. Micromolecule

b. Macromolecule

c. Monomer

d. Dimer

Answer:

(b)

Exp: A nucleic acid is a macromolecule composed of chains of monomeric nucleotides.

Q.90. The nitrogen bases present in DNA molecule are

a. adenine, guanine, uracil and cytosine.

b. adenine, guanine, thymine and cytosine.

c. adenine, thymine, uracil and cytosine.

d. adenine, thymine, uracil and guanine.

Answer:

(b)

Exp:The DNA molecule is constituted by nucleotides consisting of adenine, guanine, thymine and cytosine. Uracil is found only in RNA while thymine is found only in DNA.

Q.91. The constituents of nucleotides may be written as

a. nitrogenous base + pentose sugar.

b. nitrogenous base + nucleoside.

c. nucleoside + phosphate.

d. nucleoside + pentose sugar.

Answer:

(c)

Exp:The constituents of nucleotides are nucleoside and phosphate. Nucleotides are molecules, which comprise the structural units of RNA and DNA.

Q.92. Standard amino acids, which have been known in our body are

a. 10.

b. 15.

c. 20.

d. 25.

Answer:

(a)

Exp: Humans can produce 10 of the 20 amino acids. The others must be supplied in the food.

Q.93.The primary public catalogue for mouse genome is

a. NBRF.

b. EMBL.

c. GDB.

d. MGD.

Answer:

d)

Exp: The Mouse genome database (MGD) is the primary public catalogue for mouse genome. It includes information on mouse genetic markers, nomenclature, molecular segments, physical maps and many other aspects of mouse genome.

Q.94. The genome database maintains data created for genome mapping of

a. mouse genome project.

b. human genome project.

c. pig genome project.

d. sheep genome project.

Answer:

b)

Exp:The genome database (GDB) maintains data created for genome mapping of Human genome project. The GDB stores a vast data submitted by hundreds of investigators.

Q.95.To develop information systems in molecular biology, the NCBI was established at the

a. National Institute of health (France)

b. National Institute of health (UK)

c. National Institute of health (USA)

d. National Institute of health (England)

Answer:

(a)

Exp: To develop information systems in molecular biology the NCBI was established at the National institute of health (USA). The NCBI is the first and foremost store of publicly available genomic and proteomics data.

Q.96.One of the following provides a single query interface to organize sequence and descriptive information about genetic loci is

a. Entrez.

b. Locuslink.

c. Taxonomy browser.

d. BLAST

Answer:

(b)

Exp: Locuslink provides a single query interface to organize sequence and descriptive information about genetic loci. It presents information on official nomenclature, sequence accessions, phenotypes, EC numbers, MIM numbers, UniGene clusters, homology, map locations.

Q.97.The taxonomy browser is an original data analysis tool for visualizing the taxonomic relationships among the

a. prokaryotes.

b. eukaryotes.

c. viruses.

d. protozoans.

Answer:

(a)

Exp: The taxonomy browser is an original data analysis tool for visualizing the taxonomic relationships among the prokaryotes. It provides information on taxonomic classification of various species; it has information on over 79,000 organisms.

Q.98.Duplicated genes within a genome may also have similarities but these are referred as

a. homologs.

b. analogs.

c. orthologs.

d. paralogs.

Answer:

(d)

Exp: Duplicated genes within a genome may have similarities but these are referred as paralogs. Homologues will have the same function whereas paralogs may differ in functions.

Q.99.One of the following can be used for fast protein comparison or fast nucleotide comparison is

a. ENTREZ.

b. LOCUS LINK.

c. FASTA.

d. EST.

Answer:

(c)

Exp: FASTA stands for FAST ALL. It can be used for fast protein comparison or fast nucleotide comparison. This program achieves high level of sensitivity for similarity searching at high speed.

Q.100.In genomics one who reviews and checks newly submitted data is

a. manager.

b. director.

c. quality controller.

d. curator.

Answer:

(d)

Exp: A curator is one who reviews and checks newly submitted data. This process is called curation. He ensures that all necessary information is given for e.g.

1. Biological features are adequately described.

2. Translation of any coding regions obeys universal translation rules.

Important MCQ-based questions Biotechnology CUET chapter-Genomics And Bioinformatics Set-B

Q.1 Who coined the word genome

(a) J. Craig Venter

(b) H.Winkler

(c) Thomas Roderick

(d) V.M.Ingram

Answer:

(b) This term was coined by H.Winkler in 1920 for the full set of chromosomes. He was Professor of Botany at the University of Hamburg, Germany.

Q.2 The IUPAC code for G or C is

(a) R

(b) S

(c) Y

(d) M

Answer:

(b) According to IUPAC nomenclature S codes for G or C.

Q.3 ENTREZ is a

(a) Database.

(b) Interface.

(c) Resource.

(d) Sequence.

Answer:

(b) ENTREZ is a database through which all of its component databases can be accessed and retrieved.

Q.4 Nick is sealed by

(a) Reverse transcriptase

(b) DNA ligase

(c) DNase I

(c) DNA polymerase II

Answer:

(b) Reverse transcriptase is used in making cDNA to mRNA. DNase produces single stranded nicks and these nicks are sealed by DNA ligase.

Q.5 The complement of S is

(a) V

(b) H

(c) S

(d) D

Answer:

(c) According to IUPAC nomenclature sometime the complement symbol is same.

Q.6 Information available in SWISS- PROT is

(a) Nucleotide sequence.

(b) Three- dimensional structure of proteins.

(c) Phylogenetic analysis and alignment of proteins.

(d) Annotated protein sequence.

Answer:

(d) SWISS- PROT is a database resource provided by NCBI for annotated protein sequence.

Q.7 The three-letter code for Isoleucine is

(a) Iso

(b) Ios

(c) Iie

(d) Ile

Answer:

(d) According to IUPAC nomenclature Ile is the code for Isoleucine.

Q.8 The IUPAC code for G or A is

(a) R

(b) Y

(c) S

(d) M

Answer:

(a) According to IUPAC nomenclature R codes for G or C.

Q.9 Which tool manages redundancy in EST data

(a) ENTREZ

(b) HomoloGene Database

(c) RefSeq Database

(d) UniGene Database

Answer:

(d) Many redundant in ESTs are generated during the course of its production. Because several cDNA clones represent the same gene, to manage the redundancy in EST data UniGene database was created. The objective is to group ESTs into sets called clusters that belong to one gene.

Q.10 The IUPAC code for G or T is

(a) K

(b) R

(c) W

(d) H

Answer:

(a) According to IUPAC nomenclature for G or T is K.

Q.11 The direction of protein synthesis is

(a) 5’ to 3’.

(b) N terminal to C terminal.

(c) C terminal to N terminal.

(d) 3’ to 5’.

Answer:

(b) According to the concept of directionality proteins are synthesized in N’ to C’ direction.

Q.12 Which tool is use to discover new gene

(a) Homology based gene prediction

(b) Ab Initio Gene prediction

(c) Systemic gene prediction

(d) Non homology based gene prediction

Answer:

(a)

Q.13 The complement of A is

(a) A

(b) T

(c) G

(d) C

Answer:

(b) According to IUPAC nomenclature T is the complementary nucleotide for A

Q.14 BLAST is a

(a) Database.

(b) Sequence.

(c) Search tool.

(d) Retrieval tool.

Ans (c) Blast is a search tool to analyze sequence information.

Q.15 The three-letter code for Glutamine is

(a) Glu

(b) Glt

(c) Gly

(d) Gla

Answer:

(a) According to IUPAC nomenclature Glu is the three-letter code for Glutamine.

Q.16 The direction of nucleotide synthesis is

(a) 5’ to 3’.

(b) N terminal to C terminal.

(c) C terminal to N terminal.

(d) 3’ to 5’.

Answer:

(a) According to the concept of directionality nucleotides are synthesized in 5’ to 3’ direction.

Q.17 In IUPAC nomenclature M is the code for

(a) A or C

(b) G or C

(c) G or T

(d) T or C

Answer:

(a) According to IUPAC nomenclature M codes for A or C.

Q.18 Which of the following presents information about EC number

(a) ENTREZ

(b) FASTALL

(c) LOCUS LINK

(d) EST

Answer:

(c) The locus link presents information about official nomenclature, sequence accessions, phenotypes, EC numbers, MIM numbers, UniGene clusters, and homology, map locations.

Q.19 The complement of H is

(a) G

(b) H

(c) D

(d) M

Answer:

(d) According to IUPAC nomenclature complement of H is D.

Q.20 FASTA is used for

(a) Fast genome comparison.

(b) Fast protein comparison.

(c) Fast EST comparison.

(d) Fast cDNA comparison.

Answer:

(b) Stands for FAST ALL. It can be used for fast protein comparison or fast nucleotide comparison. This program achieves high level of sensitivity for similarity searching at high speed.

Q.21 The IUPAC code for G or A or T

(a) D

(b) N

(c) V

(d) M

Answer:

(a) According to IUPAC nomenclature G or A or T is coded by D.

Q.22 Which of the method is also known as de nova sequencing

(a) BACs sequencing

(b) Top down sequencing

(c) Random sequencing

(d) Comparative DNA sequencing

Answer:

(c) As Random sequencing does not require any pexisting information about the sequence hence it is also known as de nova sequencing.

Q.23 FISH stands for

(a) Fluorescent in silu hybridization.

(b) Fluorescent in silico hybridization.

(c) Fluorescent in situ hybridization.

(d) Fluorescent in silo hybridization.

Answer:

(c) Fluorescent in situ hybridization.

Q.24 In IUPAC nomenclature Y is the code for

(a) A or C

(b) G or C

(c) G or T

(d) T or C

Answer:

(d) According to IUPAC nomenclature Y codes for T or C.

Q.25 Who coined Genomics

(a) J. Craig Venter

(b) H.Winkler

(c) Thomas Roderick

(d) V.M.Ingram

Answer:

(c) This term was coined first time in 1986 by Thomas Roderick. He described scientific discipline of mapping, sequencing and analyzing genomes under genomics.

Q.26 What % of genome encodes for protein in weed Arabidopsis thaliana

(a) 90%

(b) 30%

(c) 20%

(d) Less than 5%

Answer:

(c) By gene prediction and gene counting it is known that out of 25,500 genes only 20% are encodes for protein.

Q.27 The one letter code for Tryptophan i

(a) A

(b) Q

(c) T

(d) W

Answer:

(d) According to IUPAC nomenclature W codes for tryptophan.

Q.28 Single stranded nicks are produced by

(a) Reverse transcriptase

(b) DNA ligase

(c) DNase I

(d) DNA polymerase II

Answer:

(c) Reverse transcriptase is used in making cDNA to mRNA. DNase produces single stranded nicks and these nicks are sealed by DNA ligase.

Q.29 FISH is

(a) A cytogenic technique.

(b) A genome sequencing technique.

(c) A genome similarity technique.

(d) A comparative genomic technique.

Answer:

(a) FISH (Fluorescent in situ hybridization) is a cytogenetic technique that can be used to detect and localize the presence or absence of specific DNA sequences on chromosomes.

Q.30 In IUPAC nomenclature N codes for

(a) G or A or T or C

(b) G or C or A

(c) G or A or T

(d) A or T

Answer:

(a) According to IUPAC nomenclature N codes for G or A or T or C.

Q.31 In microarray technology the probe is

(a) A nucleotide

(b) RNA

(c) DNA

(c) Protein

Answer:

(c) A probe can be a sequence of either RNA or DNA but in microarray technology DNA is used as a probe.

Q.32 GENSCAN can identify

(a) Protein

(b) DNA

(c) Intron

(d) Nucleotide sequence.

Answer:

(c) Gene prediction is done by using programs like GeneMark (bacterial genome) and GENSCAN (eukaryotes). GENSCAN can identify introns, exons, promotor sites and poly A signals and other gene identification algorithms.

Q.33 The complement of R is

(a) W

(b) V

(c) Y

(d) S

Answer:

(c) According to IUPAC nomenclature the complement for R is Y.

Q.34 The principal behind DNA microarray is

(a) DNA hybridization

(b) Base hybridization

(c) RNA hybridization

(d) Protein hybridization

Answer:

(b) This technology is DNA Microarray that promises to monitor the whole genome on a single microchip.

The principal behind DNA Microarray Technology is base pairing or hybridization between the nucleotides. Base pairing allows probes to hybridize to targets on the Microarray.

Q.35 Variation in cell cycle is studied by

(a) Nick translation

(b) Microarray

(c) FISH

(d) Random sequencing

Answer:

(b) Variation in cell cycle can be studied by DNA microarray technology.

Q.36 mRNA stands for

(a) Mail RNA

(b) Mature RNA

(c) Messenger RNA

(d) Male RNA

Answer:

(c) Messenger RNA is transcribed from DNA and carries message for protein synthesis.

Q.37 Identify the picture

(a) Yeast

(b) Helicobacter

(c) E.coli

(d) Caenorhabditis elegans

Answer:

(d) Caenorhabditis elegans is one of the organism whose genome has been sequenced.

Q.38 Defects in regulatory gene can be identified by

(a) Nick translation

(b) Microarray

(c) FISH

(d) Random sequencing

Answer:

(b) Defects in regulatory genes can be identified by DNA microarray technology.

Q.39 The one letter code for lysine is

(a) L

(b) M

(c) K

(d) Z

Answer:

(c) According to IUPAC nomenclature the one letter code for amino acid lysine is K.

Q.40 cDNA is

(a) Copy DNA

(b) Complementary DNA

(c) Common DNA

(d) Community DNA

Answer:

(b) Complementary DNA or cDNA is synthesized from mature RNA catalyzed by reverse transcriptase.