A determinant of order three consisting of 3 rows and 3 columns is written as:
| a2 b2 c2 |
| a3 b3 c3 |
a1(b2c3 - b3c2) - b1(a2c3 - a3c2) + c1(a2b3 - a3b2)
= a1b2c3 - a1b3c2 - b1a2c3 + b1a3c2 + c1a2b3 - c1a3b2
Properties Of Determinants
Examples
Examples 1
The value of:
| 1 b b²-ca |
| 1 c c²-ab |
is (A) 0 (B) 1 (C) -1 (D) abc
Using the property that if elements in all rows are in A.P. with same or different common differences, the determinant equals zero.
Example 2
If a ≠ p, b ≠ q, c ≠ r and:
| a q c | = 0
| a b r |
then the value of:
| p-a q-b r-c |
is (A) 1 (B) -1 (C) 0 (D) 2
DIFFERENTIATION OF A DETERMINANT
|a2(x) b2(x)| |a2(x) b2(x)| |a2'(x) b2'(x)|
For a 3×3 determinant, if Δ(x) has elements that are functions of x in one row (or column), then:
Δ'(x) = determinant with that row (or column) differentiated while others remain unchanged.
Example 3
If fr(x), gr(x), hr(x) where r = 1, 2, 3 are polynomials in x such that fr(a) = gr(a) = hr(a), r = 1, 2, 3 and:
| g1(x) g2(x) g3(x) |
| h1(x) h2(x) h3(x) |
then F(a) = 0.
SUMMATION OF DETERMINANTS
|gr b m|
|hr c n|
Then Σ(r=1 to n) Δr = |Σfr a l|
|Σgr b m|
|Σhr c n|
DETERMINANTS INVOLVING INTEGRATIONS
|a b c |
|l m n |
Then ∫[a to b] Δ(x)dx = |∫f(x)dx ∫g(x)dx ∫h(x)dx|
|a b c |
|l m n |
SPECIAL DETERMINANTS
|a b c |
|a² b² c²|
2. |1 1 1 | = (a-b)(b-c)(c-a)(a+b+c)
|a b c |
|a³ b³ c³|
3. |1 1 1 | = (a-b)(b-c)(c-a)(ab+bc+ca)
|a b c |
|a² b² c²|
4. |1 1 1 | = (a-b)(b-c)(c-a)(a+b+c-ab-ac-ca)
|a b c |
|a⁴ b⁴ c⁴|
LINEAR EQUATIONS
Homogeneous System
The system:
a2x + b2y + c2z = 0
a3x + b3y + c3z = 0
has a non-trivial solution if and only if:
| a2 b2 c2 | = 0
| a3 b3 c3 |
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If Δ ≠ 0: only trivial solution (x = y = z = 0)
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If Δ = 0: infinite solutions (non-trivial solutions exist)
CRAMER'S RULE
For the non-homogeneous system:
a2x + b2y + c2z = d2
a3x + b3y + c3z = d3
If Δ ≠ 0, then:
where:
| a2 b2 c2 | | d2 b2 c2 |
| a3 b3 c3 | | d3 b3 c3 |
Δy = | a1 d1 c1 | Δz = | a1 b1 d1 |
| a2 d2 c2 | | a2 b2 d2 |
| a3 d3 c3 | | a3 b3 d3 |
System Classifications:
SOLVED EXAMPLES
Example 1
| 6 13 20 | = 0
| 1 -6 -13 |
Example 2
| b c bα+c |
| aα+b bα+c 0 |
Example 3
If f(x) = |cos x 1 0 |
|0 1 2cos x|
FORMULAE AND CONCEPTS AT A GLANCE
- The determinant remains unaltered if its rows are changed into columns and the columns into rows.
- If all the elements of a row (or column) are zero, then the determinant is zero.
- If the elements of a row (column) are proportional (or identical) to the elements of any other row (column), then the determinant is zero.
- The interchange of any two rows (columns) of the determinant changes its sign.
- If all the elements of a row (column) of a determinant are multiplied by a non-zero constant then the determinant gets multiplied by the same constant.
- A determinant remains unaltered under a column (Ci) operation of the form Ci + λCj + μCk (j,k ≠ i) or a row (Ri) operation of the form Ri + λRj + μRk (j,k ≠ i).
- If each element in any row (column) is the sum of r terms, then the determinant can be expressed as the sum of r determinants.
- If the determinant Δ = f(x) and f(a) = 0, then (x – a) is a factor of the determinant. In other word, if two rows (or two columns) become proportional (identical) for x = a then (x – a) is a factor of determinant. In general, if r rows become identical for x = a then (x – a)^(r-1) is a factor of the determinant.
- If in a determinant (of order three or more) the elements in all the rows (columns) are in A.P. with same or different common difference, the value of the determinant is zero.
- The determinant value of an odd order skew symmetric determinant is always zero.
SOLVED EXAMPLES
Example 1
6 13 20
1 -6 -13
Options: (A) constant other than zero (B) zero (C) 100 (D) –1997
Example 2
The determinant
b+βc c bβ+c
aα+b bβ+c 0
Options: (A) a, b, c are in A.P. (B) a, b, c are in G.P. (C) a, b, c are in H.P. (D) none of these
This determinant is zero if (α² + βα + c)(αc – b²) = 0
⟹ b² = αc ⟹ a, b, c are in G.P.
Example 3
If f(x) =
1 2cos x 1
0 1 2cos x
then ∫₀π/2 f(x) dx is equal to
Options: (A) 1/4 (B) –1/3 (C) 1/2 (D) 1
∫₀π/2 f(x) dx = ∫₀π/2 cos 3x dx = [sin 3x/3]₀π/2 = -1/3
Example 4
If A, B, C are the angles of a triangle and
sin²B cotB 1
sin²C cotC 1
then Δ is equal to
Options: (A) constant other than zero (B) not a constant (C) 0 (D) none of these
Example 5
If Δ =
a x+b c
a b x+c
Options: (A) a + b + c (B) abc (C) – a – b –c (D) none of these
(x + a + b + c) times a determinant = 0 ⟹ x = –a–b–c
ASSIGNMENT PROBLEMS
Problem 1
The system of equations x + 2y + 3z = 4, 2x + 3y + 4z = 5, 3x + 4y + 5z = 6 has
Options: (A) infinitely many solution (B) no solution (C) unique solution (D) none of these
Problem 2
If
x+2 x+3 x+b
x+3 x+4 x+c
Options: (A) A.P (B) G.P (C) H.P (D) none of these
Problem 3
Δ =
2-i q 3+i
1-i 3-i r
(p, q, r ∈ real) is always
Options: (A) real (B) imaginary (C) zero (D) none of these
Problem 4
If a, b, c are roots of x³ + px² + q = 0, then
b c a
c a b
Options: (A) –p (B) q (C) p³ (D) q³
Problem 5
If the determinant
1 b 1
1 1 c
Options: (A) 8 (B) 10 (C) 12 (D) none of these
Problem 6
If
6x+2 9x+3 12x
8x+1 12x 16x+2
Options: (A) x = 0 (B) x = -11 (C) x = 97 (D) x = –11/97
Problem 7
The value of θ lying between 0 and π/2 and satisfying:
cos²θ 1+sin²θ 4sin²4θ
cos²θ sin²θ 1+4sin²4θ
Options: (A) (7π/24, 11π/24) (B) (8π/11, π/12) (C) (7π/12, 11π/24) (D) none
ANSWERS TO ASSIGNMENT
Frequently Asked Questions
A determinant is a scalar value calculated from a square matrix (e.g., 2×2, 3×3) that provides important information about the matrix, such as whether it is invertible.
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Non-zero determinant → The matrix is invertible (non-singular).
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Zero determinant → The matrix is not invertible (singular), and its rows/columns are linearly dependent.
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Row/Column Swap → Changes the sign of the determinant.
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Identical Rows/Columns → Determinant = 0.
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Scalar Multiplication → Multiplying a row/column by kkk multiplies determinant by kkk.
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Addition of Rows/Columns → Adding a multiple of one row to another doesn’t change the determinant.
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Triangular Matrix → Determinant = product of diagonal elements.
If two rows or columns are proportional (e.g., one is a multiple of the other), the determinant is zero.
Yes. The determinant can be positive, negative, or zero depending on the arrangement and orientation of the matrix’s rows/columns.
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Finding the inverse of a matrix.
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Solving systems of linear equations (Cramer’s Rule).
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Calculating areas and volumes in geometry.
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Analyzing linear transformations.
For a 2×2 matrix, the absolute value of the determinant represents the area of the parallelogram formed by its column vectors.
For a 3×3 matrix, it represents the volume of the parallelepiped.
Using Cramer’s Rule, the solution to a system of nnn equations in nnn variables can be found using determinants of the coefficient matrix and modified matrices.