Binomial Theorem Solutions


Binomial Theorem for Positive Index

(a + x)n = nC0an + nC1an-1x + nC2an-2x2 + ... + nCran-rxr + ... + nCnxn

where nC0, nC1, nC2, ..., nCn are called Binomial coefficients. The value of nCr is defined as

nCr = n! / [r! (n - r)!] = n(n-1)(n-2)...(n-r+1) / (1 × 2 × 3 × ... × r)

Observations

  1. There are (n+1) terms in the expansion of (a + x)n.
  2. Sum of powers of x and a in each term in the expansion of (a + x)n is constant and equal to n.
  3. The general term in the expansion of (a + x)n is the (r+1)th term, given as tr+1 = nCran-rxr.
  4. The binomial coefficients in the expansion of (a + x)n equidistant from the beginning and the end are equal. That means nCr is equal to nCn-r.

Middle Terms

(a) When n is even
Clearly in this case we have only one middle term namely tn/2 + 1. Thus middle term in the expansion of (a + x)n will be nCn/2 an/2xn/2 term.

(b) When n is odd
Clearly in this case we have two middle terms namely t(n+1)/2 and t(n+3)/2. That means the middle terms in the expansion of (a + x)n are nC(n-1)/2a(n+1)/2x(n-1)/2 and nC(n+1)/2a(n-1)/2x(n+1)/2.

Greatest Term

Greatest Term

If tr and tr+1 be the rth and (r + 1)th term in the expansion of (1 + x)n, then

tr+1 / tr = nCr Xr / nCr-1 Xn-r= n - r + 1 /r = x

Let numerically, tr+1 be the greatest term in the above expansion. Then tr+1 ≥ tr or

tr+1tr ≥ 1 ⇒n - r + 1 r|x| ≥ 1⇒r ≤ (n+1)|x| 1+|x|

Now shifting values of n and x in (2), we get rm + f or rm

Where m is a positive integer, f is a fraction such that 0 ≤ f < 1.
Now if f = 0 then tm+1 and tm both the terms will be numerically equal and greatest while if f ≠ 0, then tm+1 is the greatest term of the binomial expansion.
i.e. to find the greatest term (numerically) in the expansion of (1 + x)n.

  1. Calculate m = (n + 1) |x|
    —————————
    (1 + |x|)
  2. If m is integer, then tm and tm+1 are equal and are greatest term.
  3. If m is not integer, then t[m]+1 is the greatest term (where [.] denotes the greatest integer function).

PROPERTIES OF BINOMIAL COEFFICIENTS

For the sake of convenience, the coefficients nC0 , nC1 , ..., nCr ,..., nCn are usually denoted by C0 , C1 , ..., Cr , ..., Cn respectively

  1. C0 + C1 + C2 + ... + Cn = 2n
  2. C0 − C1 + C2 − ... + (−1)nCn = 0
  3. C0 + C2 + C4 + ... = C1 + C3 + C5 + ... = 2n−1
  4. nCr₁ = nCr₂ ⇒ r1 = r2 or r1 + r2 = n
  5. nCr + nCr-1 = n+1Cr
  6. r·nCr = n·n−1Cr-1
  7. nCr/r+1 = n+1Cr+1/n+1

(1 + x)n = C₀ + C₁x + C₂x² + ... + Cₙxⁿ ...(1)
and ( x + 1 )n = C₀xⁿ + C₁xn-1 + ... + Cₙ ...(2)
multiplying (1) and (2), we get
(1 + x )2n = (C₀ + C₁x + C₂x² + ... + Cₙxⁿ)(C₀xⁿ + C₁xn-1 + ... + Cₙ)
Equating the coefficient of xn+1, we get

C₀C₁ + C₁C₂ + ... + Cn-1Cₙ = 2nCn+1 = (2n)!
(n + 1)! (n - 1)!

BINOMIAL THEOREM FOR ANY INDEX

(1 + x)n = 1 + nx + n(n - 1)2! x2 + … + n(n - 1)…(n - r + 1)r! xr + … terms up to ∞

Observations

  1. Expansion is valid only when −1 < x < 1
  2. nCr can not be used because it is defined only for natural numbers, so nCr will be written as n(n - 1)…(n - r + 1)r!.
  3. As the series never terminates, the number of terms in the series is infinite.
  4. General term of the series (1 + x)−n = Tr+1 = (−1)rn(n+1)(n+2)…(n+r-1)r! xr

Important Expansions

  1. (1 + x)-1 = 1 − x + x2 − x3 + ... + (−1)rxr + ...
  2. (1 − x)-1 = 1 + x + x2 + x3 + ... + xr + ...
  3. (1 + x)-2 = 1 − 2x + 3x2 − 4x3 + ... + (−1)rr(r + 1)xr + ...
  4. (1 − x)-2 = 1 + 2x + 3x2 + 4x3 + ... + (r + 1)xr + ...
  5. (1 + x)-3 = 1 − 3x + 6x2 − 10x3 + ... + (−1)r(r + 1)(r + 2)/r! xr + ...
  6. (1 − x)-3 = 1 + 3x + 6x2 + 10x3 + ... + (r + 1)(r + 2)/r! xr + ...
  7. (1 − x)-p/q = 1 + p/1! (x/q) + p(p + q)/2! (x/q)2 + ...

Multinomial Expansion

In the expansion of (x1 + x2 + ... + xn)m where m, n ∈ ℕ and x1, x2, ..., xn are independent variables, we have

  1. Total number of terms in the expansion = C(m + n - 1, n - 1)
  2. Coefficient of x1r1 x2r2 x3r3 ... xnrn (where r1 + r2 + ... + rn = m, ri ∈ ℕ ∪ {0}) is
    m!r1! r2! ... rn!

Sum of all the coefficients is obtained by putting all the variables xi equal to 1 and it is equal to nm.

Formulas and Concepts at a Glance

  1. (a + x)n = nC0an + nC1an-1x + nC2an-2x2 + ... + nCran-rxr + ... + nCnxn = ∑r=0nnCrxr
  2. (a + x)n + (a - x)n = ∑r=0nnCrxr[1 + (-1)r] = 2(nC0an + nC2an-2x2 + ...)
  3. (a + x)n - (a - x)n = ∑r=0nnCrxr[1 - (-1)r] = 2(nC1an-1x + nC3an-3x3 + ...)
  4. C0 + C1 + C2 + ... + Cn = 2n
  5. C0 - C1 + C2 - ... = 0
  6. C0 + C2 + C4 + ... = C1 + C3 + C5 + ... = 2n-1
  7. nCr + nCr-1 = n+1Cr
  8. nCr = [(n - r + 1) / r] nCr-1
  9. rnCr = nn-1Cr-1
  10. nCr / (r + 1) = n+1Cr+1 / (n + 1)
  11. There are (n + 1) terms in expansion.
  12. Binomial coefficients of terms equidistant from beginning and end are equal.
  13. The general term of the expansion is nCran-rxr, this is in fact the (r+1)th term from the beginning.
  14. If n is even, there is only one middle term namely (n/2 + 1)th and is equal to nCn/2an/2xn/2.
  15. If n is odd, there are two middle terms namely (n+1)/2 th and (n+3)/2 th and are equal to nC(n-1)/2a(n+1)/2x(n-1)/2 and nC(n+1)/2a(n-1)/2x(n+1)/2 respectively.
  16. Binomial coefficient of middle term is the greatest binomial coefficient occurring in the expansion.