Binomial Theorem for Positive Index
(a + x)n = nC0an + nC1an-1x + nC2an-2x2 + ... + nCran-rxr + ... + nCnxn
where nC0, nC1, nC2, ..., nCn are called Binomial coefficients. The value of nCr is defined as
nCr = n! / [r! (n - r)!] = n(n-1)(n-2)...(n-r+1) / (1 × 2 × 3 × ... × r)
Observations
- There are (n+1) terms in the expansion of (a + x)n.
- Sum of powers of x and a in each term in the expansion of (a + x)n is constant and equal to n.
- The general term in the expansion of (a + x)n is the (r+1)th term, given as tr+1 = nCran-rxr.
- The binomial coefficients in the expansion of (a + x)n equidistant from the beginning and the end are equal. That means nCr is equal to nCn-r.
Middle Terms
(a) When n is even
Clearly in this case we have only one middle term namely tn/2 + 1. Thus middle term in the expansion of (a + x)n will be nCn/2 an/2xn/2 term.
(b) When n is odd
Clearly in this case we have two middle terms namely t(n+1)/2 and t(n+3)/2. That means the middle terms in the expansion of (a + x)n are nC(n-1)/2a(n+1)/2x(n-1)/2 and nC(n+1)/2a(n-1)/2x(n+1)/2.
Greatest Term
Greatest Term
If tr and tr+1 be the rth and (r + 1)th term in the expansion of (1 + x)n, then
tr+1 / tr = nCr Xr / nCr-1 Xn-r= n - r + 1 /r = x
Let numerically, tr+1 be the greatest term in the above expansion. Then tr+1 ≥ tr or
tr+1tr ≥ 1 ⇒n - r + 1 r|x| ≥ 1⇒r ≤ (n+1)|x| 1+|x|
Now shifting values of n and x in (2), we get r ≤ m + f or r ≤ m
Where m is a positive integer, f is a fraction such that 0 ≤ f < 1.
Now if f = 0 then tm+1 and tm both the terms will be numerically equal and greatest while if f ≠ 0, then tm+1 is the greatest term of the binomial expansion.
i.e. to find the greatest term (numerically) in the expansion of (1 + x)n.
- Calculate m = (n + 1) |x|
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(1 + |x|) - If m is integer, then tm and tm+1 are equal and are greatest term.
- If m is not integer, then t[m]+1 is the greatest term (where [.] denotes the greatest integer function).
PROPERTIES OF BINOMIAL COEFFICIENTS
For the sake of convenience, the coefficients nC0 , nC1 , ..., nCr ,..., nCn are usually denoted by C0 , C1 , ..., Cr , ..., Cn respectively
- C0 + C1 + C2 + ... + Cn = 2n
- C0 − C1 + C2 − ... + (−1)nCn = 0
- C0 + C2 + C4 + ... = C1 + C3 + C5 + ... = 2n−1
- nCr₁ = nCr₂ ⇒ r1 = r2 or r1 + r2 = n
- nCr + nCr-1 = n+1Cr
- r·nCr = n·n−1Cr-1
- nCr/r+1 = n+1Cr+1/n+1
(1 + x)n = C₀ + C₁x + C₂x² + ... + Cₙxⁿ ...(1)
and ( x + 1 )n = C₀xⁿ + C₁xn-1 + ... + Cₙ ...(2)
multiplying (1) and (2), we get
(1 + x )2n = (C₀ + C₁x + C₂x² + ... + Cₙxⁿ)(C₀xⁿ + C₁xn-1 + ... + Cₙ)
Equating the coefficient of xn+1, we get
C₀C₁ + C₁C₂ + ... + Cn-1Cₙ = 2nCn+1 = (2n)!
(n + 1)! (n - 1)!
BINOMIAL THEOREM FOR ANY INDEX
(1 + x)n = 1 + nx + n(n - 1)⁄2! x2 + … + n(n - 1)…(n - r + 1)⁄r! xr + … terms up to ∞
Observations
- Expansion is valid only when −1 < x < 1
- nCr can not be used because it is defined only for natural numbers, so nCr will be written as n(n - 1)…(n - r + 1)⁄r!.
- As the series never terminates, the number of terms in the series is infinite.
- General term of the series (1 + x)−n = Tr+1 = (−1)rn(n+1)(n+2)…(n+r-1)⁄r! xr
Important Expansions
- (1 + x)-1 = 1 − x + x2 − x3 + ... + (−1)rxr + ...
- (1 − x)-1 = 1 + x + x2 + x3 + ... + xr + ...
- (1 + x)-2 = 1 − 2x + 3x2 − 4x3 + ... + (−1)rr(r + 1)xr + ...
- (1 − x)-2 = 1 + 2x + 3x2 + 4x3 + ... + (r + 1)xr + ...
- (1 + x)-3 = 1 − 3x + 6x2 − 10x3 + ... + (−1)r(r + 1)(r + 2)/r! xr + ...
- (1 − x)-3 = 1 + 3x + 6x2 + 10x3 + ... + (r + 1)(r + 2)/r! xr + ...
- (1 − x)-p/q = 1 + p/1! (x/q) + p(p + q)/2! (x/q)2 + ...
Multinomial Expansion
In the expansion of (x1 + x2 + ... + xn)m where m, n ∈ ℕ and x1, x2, ..., xn are independent variables, we have
- Total number of terms in the expansion = C(m + n - 1, n - 1)
- Coefficient of x1r1 x2r2 x3r3 ... xnrn (where r1 + r2 + ... + rn = m, ri ∈ ℕ ∪ {0}) is
m!⁄r1! r2! ... rn!
Sum of all the coefficients is obtained by putting all the variables xi equal to 1 and it is equal to nm.
Formulas and Concepts at a Glance
- (a + x)n = nC0an + nC1an-1x + nC2an-2x2 + ... + nCran-rxr + ... + nCnxn = ∑r=0nnCrxr
- (a + x)n + (a - x)n = ∑r=0nnCrxr[1 + (-1)r] = 2(nC0an + nC2an-2x2 + ...)
- (a + x)n - (a - x)n = ∑r=0nnCrxr[1 - (-1)r] = 2(nC1an-1x + nC3an-3x3 + ...)
- C0 + C1 + C2 + ... + Cn = 2n
- C0 - C1 + C2 - ... = 0
- C0 + C2 + C4 + ... = C1 + C3 + C5 + ... = 2n-1
- nCr + nCr-1 = n+1Cr
- nCr = [(n - r + 1) / r] nCr-1
- rnCr = nn-1Cr-1
- nCr / (r + 1) = n+1Cr+1 / (n + 1)
- There are (n + 1) terms in expansion.
- Binomial coefficients of terms equidistant from beginning and end are equal.
- The general term of the expansion is nCran-rxr, this is in fact the (r+1)th term from the beginning.
- If n is even, there is only one middle term namely (n/2 + 1)th and is equal to nCn/2an/2xn/2.
- If n is odd, there are two middle terms namely (n+1)/2 th and (n+3)/2 th and are equal to nC(n-1)/2a(n+1)/2x(n-1)/2 and nC(n+1)/2a(n-1)/2x(n+1)/2 respectively.
- Binomial coefficient of middle term is the greatest binomial coefficient occurring in the expansion.